Question

2 ) Determine nature of roots of the quadratic equation x2 + 2x – 9 =0
Solution : Compare x2 + 2x – 9 = 0 with ax2 + bx + c = 0 , a = 1 , b = 2 , c = -9 ∴ b2 – 4ac = 22 – 4x x = 4 -
= 40 , ∴ b2 – 4ac > 0 ∴ The roots are​

Answer 1

Answer:this pic may be helpful for you. Step-by-step explanation:It may be helpful for you.

Answer 2

The nature of the roots of the quadratic equation x² + 2x - 9 = 0 is real and distinct

To determine the nature of the roots of the quadratic equation x² + 2x - 9 = 0, we can use the discriminant formula, which is:

b² - 4ac

where a, b, and c are the coefficients of the quadratic equation ax² + bx + c = 0.

In this case, a = 1, b = 2, and c = -9, so the discriminant is:

b² - 4ac = (2)² - 4(1)(-9) = 4 + 36 = 40

Since the discriminant is positive (i.e., greater than zero), the quadratic equation has two real and distinct roots.
Therefore, the nature of the roots of the quadratic equation x² + 2x - 9 = 0 is real and distinct.

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