Question

2. Determine the point on the graph of equation 2x+5y =19 whose ordinate is (3/2) times its abscissa

Answer 1

Answer:

The required point is (2,3).

Step-by-step explanation:

Let x be the abscissa of the given line 2x+5y=19, then by given condition,

Ordinate (y)=112× Abscissa

⇒ y=32x

On putting y=32x in given equation, we get

2x+5(32)x=19

⇒ 4x+15x=19×2

⇒ 4x+15x=38

⇒ 19x=38

⇒ x=3819

∴ x=2

On substituting the value of x in Eq. (i), we get

y=(3)/(2)xx2=3implies " " y=3`

Hence, the required point is (2,3).

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