2. Determine the resistance of a coil connected to a 150Vsupplywhen a current of (a) 75Ma (b) 300μA flows through it.
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Answer: 2* 10 ^-6 Ω and 5*10^5 Ω
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Explanation:
Potential difference (V) = 150 V
Case I
Current (I) = 75 MA = 75 * 10 ^6 A
So, Resistance (R) = V/I = 150 /75 * 10 ^6 = 2* 10 ^-6 Ω
Case II
Current (I) = 300μA = 300*10^-6 A
So, Resistance (R) = V/I = 150 /300*10^-6 = 5*10^5 Ω
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