Question

2 dice are thrown at the same time and the product of numbers appearing on them is noted. Find the probability that the product is at least 9

Answer 1

GIven that two dice are rolled.

Then the probability of outcomes n(S) = 6 * 6

                                                                 = 36.

Let E be the event of getting a product less than 9.

The number whose product is less than 9 

= {1,1},{1,2},{1,3},{1,4},{1,5},{1,6},{2,1},{2,2},{2,3},{2,4}{3,1},{3,2},{4,1},{4,2},{5,1},{6,1}

= 16.


Therefore the required probability

P(E) = n(E)/n(S)

        = 16/36

        = 4/9.


Hope this helps!
please mark it as brainliest answer

Answer 2

Answer: Let us take this event as B

Total number of outcomes = 36

So, The posibility of getting sum as  9 = 4   (i.e :-6+3=9 ,3+6=9 ,5+4=9 , 4+5=9 )  which is our conditions.

Thus, The probability that the product is 9 = 4/36 = 1/9