2 dice are thrown simultaneously 500 times each time the sum of no. Appeearing on their top were noted and recordedas given in following tabel
sum 2 /3 / 4 /5 / 6 / 7 /8 /9 / 10 / 11 /12
frequency. 14/ 30/ 42/ 55/ 72/ 75/ 70/ 53/ 46/ 28/ 15
If dice are thrown once more what is the probability of getting a sum
3
more than 10
between 8 & 12
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total probibility =500
to find = a sum of 3 and more than 10 and between 8&12
solution- the probility of 3 = no. of frequency / total probility
the p(3)= 30/500
more then 10 in which be include only 11 and 12 so 28 and 15 and its sum is 43
p(more than 10)=43/500
between 8 and 12 be take 9,10,11 ,
so p(between 8 and 12 ) = 127/500
to find = a sum of 3 and more than 10 and between 8&12
solution- the probility of 3 = no. of frequency / total probility
the p(3)= 30/500
more then 10 in which be include only 11 and 12 so 28 and 15 and its sum is 43
p(more than 10)=43/500
between 8 and 12 be take 9,10,11 ,
so p(between 8 and 12 ) = 127/500
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