2 dice are thrown simultaneously the probabiliity of getting the sum divisible by 3 is
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the probability of getting sum divisible by 3= 1/6
arbaz20:
sorry
thats wrong answee
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Total no of outcomes =36
No of favorable outcomes =12
Probability of getting the sum divisible by 3 is 12/36 =1/3
No of favorable outcomes =12
Probability of getting the sum divisible by 3 is 12/36 =1/3
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