Question

2 dice are thrown simultaneously what is the probability of sum as multiple of 4

Answer 1

Answer:

total no. of observation=36

sample space ={(1,3),

(2,2),

(2,6),

(3,1),

(3,5),

(4,4),

(5,3),

(6,2),

(6,6)}

no.of outcome=9

p(E)=no. of favourable outcome/total no. of outcomes

p(getting sum as multiple of 4)=9/36

=1/4 Answer

Step-by-step explanation:

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