2 dice are thrown togather what is the probablity of getting a doublet
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p(getting doublet)=6/36=1/6
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hey friend here is u r answer
when two dice are thrown the probability of getting a doublet is
sample space:(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)
(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)
(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)
(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)
(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)
(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)
total possibility of an outcome:36
no. of possibilities :6/36
=1/6
I hope this helps.
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