Question

2 dice is rollaed simultaneously what is the probability that getting the sum as 4

Answer 1

probability = 3/36 = 1/12

hope it helped u

Answer 2

Total number of possible outcomes when 2 dice are rolled = 6 * 6

                                                                                          n(S)  = 36.



Let E be the event of getting a sum 4 = {1,3},{3,1},{2,2}

 n(E) = 3.


Therefore, required probability P(E) = n(E)/n(S)

                                                            = 3/36

                                                            = 1/12.


Hope this helps!