Question

2 different coins are tossed randomly .find the probability of getting 1 tail​

Answer 1

Answer:

5/6 is the probability of getting one tail....

Answer 2

Let E3 = event of getting 1 tail. Then,

E3 = {TH, HT} and, therefore, n(E3) = 2.

Therefore, P(getting 1 tail) = P(E3) = n(E3)/n(S) = 2/4 = 1/2

Hope it helps :)