2 different dice are thrown together find the probablity that the no. obtained is a doublet of odd no.s
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hey
Total no.of possible outcomes = 36
No.of doubles = 6
No.of odd doubles = 3
No.of favourable outcomes = 3
P (E) = no.of favourable outcomes / total no.of possible outcomes
= 3/36
= 1/12
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P(e) is 0.08
hope it helps
hope it helps
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