Question

2 digit numbers which leaves a remainder 1 on division by 5 write down the sequence

Answer 1

Answer:

Sequence of natural numbers leaving remainder 1 on division by 3 = 1,4,7,10,13...

Sequence of natural numbers leaving remainder 2 on division by 3 = 2,5,8,11,14...

Step-by-step explanation:

Step 1: Write the multiples of 3. That is 3,6,9,12...

These are the numbers leaving remainder 0 on division by 3. Also on divide 0 by 3, the remainder is 0. Therefore, the numbers leaving remainder 0 on division by 3 are, 0,3,6,9,12

Step2: If you want remainder 1 on divsion by 3, add 1 in the above sequance of numbers. That is, 1,4,7,10,13...

If you want remainder 2 on divsion by 3, add 2 in the above sequance of numbers. That is, 2,5,8,11,14...

Step-by-step explanation:

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Answer 2

Answer:

21

Step-by-step explanation:

If 21 is divided by 5.

then the required equation will be:

5)21(4

20

____

01