Question

2. Discuss the nature of roots of the equation x2 - 3x - 9 = 0​

Answer 1

Equation:

x²-3x-9=0

Determinant: b²-4ac=∆

∆=3²-4(-9)(1)

∆=9+36

∆=45

∆>0

Since determinant is greater than zero, the equation has two real, distinct roots.

Answer 2

Answer:

drisciminant(D)= b2-4ac

a = 1

b=-3

c=-9

putting values

(-3)(-3)-4(1)(-9)

9+36

45

45 is greater than 0

so, this equation has two different roots.