Question

2. Distribute the electrons for the given element (a) Sodium (b) Chlorine​

Answer 1

Answer:

The distribution of electrons in the sodium atom is as follows: In the first orbit or K-shell = 2 electrons. In the second orbit or L-shell = 8 electrons.

In writing the electron configuration for Chlorine the first two electrons will go in the 1s orbital. Since 1s can only hold two electrons the next 2 electrons for Chlorine go in the 2s orbital. The next six electrons will go in the 2p orbital. ... Therefore the Chlorine electron configuration will be 1s22s22p63s23p5.

Answer 2

Answer:

*Sodium* - Atomic number is 11 , so electron distribution will be ( 2,8,1) .

*Chlorine* - Atomic number is 17 , so electron distribution will be (2,8,7).

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