Question

2. Divide:
(i) -39x^4 by √13x^2​

Answer 1

sqrt(117) x

Step-by-step explanation:

let a = -39x^4 / sqrt(13) x^2

squaring both sides

a^2 = 39 * 39 x^4/ 13 x^2

a^2 = 117 x^2

square rooting both sides

a = sqrt(117) x

Answer 2

Answer:

$\sf\bold\red{AnswEr}$

$By \: factor \: theorem,if 35 and −35  \: are \: the \: zeroes \: of \:the m \:polynomial \: then \:  x−35=0 and x+35=0$

$⇒(x−35)(x+35)=0 is \: one \: of \: the \: factor \: of \: the \: polynomial.$

$⇒x2−35=0$

$The \: other \: factor \: are \: calculated \: by \: dividing \: the \: polynomial \: by  \: x2−35 \\ \\ 3x4−15x3+13x2+25x−30÷x2−35</h3><h3> \\ \\ The \: other \: factor \: is 3x2−15x−18 \\ \\ 3(x2−5x−6) \\ \\ =3(x2−6x+x−6) \\ \\ =3(x−6)(x+1) \\ \\ ∴ the \: factors \: of \: the \: polynomial \: are (x−35),(x+35),(x−6),(x+1)</h3><p></p><h3>The \: other \: zeroes \: of \: the \: polynomial \: are 6,−1</h3><p></p><p></p><p>$