Question

2. Divide the polynomial p(x) by the polynomial g(x) and find the quotient and the remainder:
P(x) = x -3x +4x+5 g(x) = x +1-x
3. The coach of a cricket team buys 3 bats and 6 balls for Rs. 3900. Later, she buys another bat and 3 more balls of the
same kind for Rs. 1300. Represent this situation algebraically and geometrically.
4. Solve 2x+3y = 11 and 2x-4y = -24 and hence find the value of 'm' for which y = mx+3.​

Answer 1

Step-by-step explanation:

answer no 3

Reffer imagr.

let rate of bat = xRs.

and rate of ball = yRs.

3x+6y=3900.....(i)

and x+3y=1300.....(ii)

or x=(1300−3y)

now equation (i) can be written as

3(1300−3y)+6y=3900

3900−9y+6y=3900

∴y=0

Ans:- x=1300

Answer no 4

Given equations are

2x+3y=11−−−−(1)

2x−4y=−24−−−−(2)

Form (1)

2x+3y=11

⇒2x=11−3y

⇒x=

2

11−3y

−−−(3)

substituting x in(2)

2x−4y=−24

⇒2(

2

11−3y

)−4y=−24

⇒11−3y−4y=−24

⇒11−7y=−24

⇒7y=35

⇒y=35/7

⇒y=5.

putting y = 5 in (3)

x=

2

11−3(5)

⇒x=

2

11−15

⇒x=−4/2

∴x=−2.

Hence x = -2 and y = 5 is the solution of the

equation.

Now, we have to find m

y=mx+3 ∴m=−1

5=3(−2)+3

5−3=−2m⇒−2m=2

⇒m=−2/x=−1