2 dm' of 4M H2SO4 is mixed with 3 dm3
water. What is the molarity of the final
solution ? [1.6]
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3
Answer:
1.6
Explanation:
As we know C =n/V
here it is given that C = 4M and V = 2 dm3/ Ltr
so no. of moles, n = 4×2 = 8
and then 3 dm3/Ltr water is added
so mix. volume is 5 dm3. And no of moles will be same,
n= 8
so Conc,C = n/V
C = 8/5 = 1.6
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I hope it helpled you
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