2.
Dr. Smith wants to do a research on light accuracy and a sum of Rs. 32000 was
invested in a research in two parts. One part was deposited at 8% pa, and the
other part was deposited at 12% p.a. The sum earns an interest of 9% pa Find the
difference (in Rs.) of the two parts.
A 12000
B 14000
C 16000
D 10000
Answers
Answer:
dr samit javh ha v aha hz shs 12000
Answer:
The correct answer is option (c) 16000
Step-by-step explanation:
Given data
A sum of Rs.32000 was invested in two parts
part one was deposited at 8% per annum
part two was deposited at 12% per annum
the earned interest on total sum per annum = 9%
here we need to find difference between two invested parts
Let x and y be the invested two parts
sum two parts x + y = 32000 _(1)
from given data interest earned per annum = 9%
interest earned =
= 9 (320)
= 2880 Rs.
now calculate interest on both parts x and y
interest on x at rate of interest 12% for 1 years
here Principal amount (P) = x, Rate (R) = 12% , time (T) = 1 year
interest =
=
=
interest on y at rate of interest 8% for 1 years
here Principal amount (P) = y , Rate (R) = 8%, time (T) = 1 year
interest =
=
from given data interest earned = Rs.2880 which is equals to interest earned on both x and y
⇒
⇒
⇒ 3x + 2y = 72000 _(2)
Now solve (1) and (2)
3 × (1) ⇒ 3x + 3y = 96000 _(4)
1 × (2) ⇒ 3x +2y = 72000 _(5)
do (4) - (5)
⇒ 3x + 3y - 3x - 2y = 96000 - 72000
y = 24000 Rs
therefore x = 32000 - 24000 = 8000
the invested parts x = 8000 and y = 24000
difference between x and y = 24000 - 8000 = Rs.16000