Math, asked by Jidnyasavartak05, 4 months ago


2. Draw an acute angled A PQR. Draw all of its altitudes. Name the point of concurrence as 'O'​

Answers

Answered by Anonymous
2

Answer:

Image result for Draw an acute angled A PQR. Draw all of its altitudes. Name the point of concurrence as 'O'​

Hence, ∆PQR is the required triangle with altitudes PL, QM and RN on sides QR, RP and PQ respectively with O as the point of concurrence of all the three altitudes.

Step-by-step explanation:

Answered by tanuja200746
4

Answer:

sτєρs σƒ cσทsτrυcτiσท :

(i) ∂rαω αทy αcυτє αทgℓє∂ ∆ρqr.

(ii) ωiτн ρ αs cєทτrє, ∂rαω αท αrc τнατ cυτ τнє si∂є qr ατ x αท∂ y.

(iii) ωiτн x αs cєทτrє αท∂ rα∂iυs мσrє τнαท нαℓƒ σƒ xy, ∂rαω αท αrc вєℓσω qr. ωiτн y αs cєทτrє αท∂ sαмє rα∂iυs ∂rαω αทστнєr αrc τнατ cυτ τнє ρrєviσυs αrc ατ α.

(iv) jσiท ρα τнατ iทτєrsєcτ qr ατ ℓ. sσ, ρℓ is τнє αℓτiτυ∂є σท si∂є qr.

iท τнє sαмє мαททєr, ∂rαω qм⊥ρr αท∂ rท⊥ρq.

нєทcє, ∆ρqr is τнє rєqυirє∂ τriαทgℓє ωiτн αℓτiτυ∂єs ρℓ, qм αท∂ rท σท si∂єs qr, rρ αท∂ ρq rєsρєcτivєℓy ωiτн σ αs τнє ρσiทτ σƒ cσทcυrrєทcє σƒ αℓℓ τнє τнrєє αℓτiτυ∂єs.

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