Question

2 drops of equal radius falling through air with steady velocity of 5cm per second if 2 drop coalesce then its ter minal velocity will be

Answer 1

SoluTion :-

Radius = r

$\sf {\frac{4}{3} \pi R^{3}}\\\\\\\sf {\Rightarrow 2 \times \frac{4}{3} \pi r^{3} }\\\\\\\sf {\Rightarrow R = 2^{1/3}r}\\\\\\\\\boxed {\sf {\because \ v_0 \propto r^{2}}}\\\\\\\sf {\therefore \frac{v_{01}}{v_{1}} =\frac{R^{2}}{r^{2}} =\frac{(2^{1/3})^{2}}{r^{2}} =2^{2/3} }$

$\sf {v_{01}=v_{0}2^{2/3}=5(4)^{1/3}}$