Question

2. Dry saturated steam at 6.5 bar with negligible velocity expands isentropically in
a convergent divergent nozzle to 1.4 bar and dryness fraction 0.956. Determine the final
velocity of steam from the nozzle if 13% heat is loss in friction. Find the % reduction in
the final velocity.​

Answer 1

Answer:

h1= 2920 kJ/kgh2= 2810 kJ/kgh3= 2590 kJ/kgh3’ = 2638 kJ/kgVel. at Throat = 616.43 m/sDischarge = 1.99 m3/sSp. Vol. at Throat = 0.2 m3/kgMass flow rate = 9.95 kg/sSp. Vol. at Exit = 0.4 m3/kgVel. at Exit = 839 m/sExit Area = 50 cm2

7.Steam enters through a convergent divergent nozzle at 19 bar and 523K. The discharge pressure is 0.2 bar, the expansion is uniformthroughout the operation. At convergent portion there is no frictionloss. Whereas, at divergent portion there is 20 percent friction loss.Calculate the throat area and exit area of the nozzle if the mass flowrate of steam is 15 kg/s. Also draw the enthalpy versus entropydiagram for the given case.n = 1.3 for superheated steamP2= 10.37 bar, Specific volume at inlet = 0.1179 m3/kg andSpecific volume at throat = 0.187 m3/kg.Velocity at throat = 503 m/s and Velocity at exit = 1088.8 m/sS1 = S2 = S3Dryness fraction at exit X3= 0.811Throat area = 0.0055 m2and exit area = 0.085 m2

Explanation:

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Answer 2

Answer:

6.72 % reduction in the final velocity.​

Explanation:

Given data:

Exit pressure $(P2) = 1.4 bar$

Dryness fract ion$(X2) = 0.956$

Heat loss $= 13%$

To Find:

The percent reduction in final velocity

Solution:

From steam table for initial pressure P1 = 6.5bar, take values h1 =

$h1 = 2758.8KJ/Kg$

Similarly, at 1.4 bar,

$hfg2 = 2231.9 KJ/Kg$

$hf2 = 458.4KJ/Kg$

$h2 = hf2 + X2 hfg2$

$= 458.4 + (0.956) 2231.6$

$h2 = 2592.1 KJ/Kg$

Final velocity $(V2) = Rt (2000(h1-h2) )$

$V2 = 577.39 m/s$

Heat drop is$13= 0.13$

Nozzle efficiency (η) $= 1- 0.13 = 0.87$

Velocity of s team by considering the nozzle efficiency,

$y (V2) = Rt (2000(h1-h2) ) * n$

$V2 = 538.55 m/s$

              $= reduction \ in \ final\ velocity \\= 6.72%$