Question

2.
dx
√3x-2 integrate from limits 1 to 2​

Answer 1

Step-by-step explanation:

We have,

$\int \limits^{2}_{1} \frac{dx}{ \sqrt{3} x - 2}$

$= [ \frac{ ln( \sqrt{3} x - 2) }{ \sqrt{3} } ]^{2}_{1}$

$= \frac{1}{ \sqrt{3} } ( ln(2 \sqrt{3} - 2 ) - ln( \sqrt{3} - 2 ) )$