2)
e the following quadratic equations.
Solve the following quad
i) 8x^2+ 2x + 1 = 0
ii) 2x^2 – in root3 x + 1 = 0
iii) 3x^2 – 7x + 5 = 0
iv) x^2- 4x + 13 = 0
Answers
Answered by
1
1) D is -ve ,so there are no real solution.
D=b²-4ac
=-28
2) D is -ve ,so no real roots
D=(-root3)²_4ac = -5
3) D is -ve, no real roots
D= -11
4)D is -ve no real roots
D = -36
Answered by
2
Answer:
roots are not real in any of equation .
Step-by-step explanation:
1) discriminant(D) =b^2 -4*a*c
on comparing given equation with ax^2+b x+c =0,we get,
a=8,b=2,c=1,
D =2^2-4*8*1
D=-28 ,therefore roots are imaginary.
2) D= √3^2-4*2*1=-5
roots are imaginary.
3)D=(-7^2)-4*3*5=-11,
therefore roots are imaginary.
4)D=(-4^2)-4*1*13=-36,
roots are imaginary.
because D <0 in all cases.
hope you liked my answer:)
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