Question

2) Each card bears one letter from the word 'airthmetic' the cards are placed
on a table upside down. To find the probability that a card drawn bears the
letter 't' complete the activity. 'S' is the (171..) :: n(S)=(..........)
Event A: card drawn bears the letter 't'.
Total cards bears the letter 't' (............
.. n(A) = 2
.. P (A) = n(A) :: P(A) = CS
8+42​

Answer 1

Probability of T = 1/5

Step-by-step explanation:

Each card bears one letter from the word 'airthmetic' the cards are placed

on a table upside down

A  - 1

C - 1

E - 1

H - 1

I  - 2

M - 1

R - 1

T - 2

Total cards = 10

Number of Cards bearing T  = 2

Probability of T = 2/10  =  1/5

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