(2) Each card bears one letter from the word "PROBABILITY' The cards are
placed on a table upside down. Find the probability that: (i) a card drawn
bears the letter 'B'. (ii) a card drawn bears a vowel.
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Answered by
12
Answer:
sample space be 'S'
S = { P , R , O , B, A , B, ,I, L,I,T,Y }
n(S) = 11
I) Let A be the the event that the card drawn bears letter 'B'
A = { B , B } n(A) = 2 P(A)= n(A)/n(S) = 2/11
ii) Let B be The event that the card drawn bears a vowel .
B = { O , A , I , I }
n(B) = 4. P(B) = n(B)/n(S) = 4/11
i)2/11 ii) 4/11
Hope this helps you and this chapter is very easy if you understand the concepts well ...
Answered by
0
Answer:
i) 2/11
ii) 4/11
Step-by-step explanation:
By probability method
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