Question

2. Each of the sets A, B and C consist of 23 people each. If the total number of people is 37, how
many people belong to at least two sets?​

Answer 1

Step-by-step explanation:

23 +23+23=69

69\23

3 seats for each

please mark as brainliest

Answer 2

Answer: There are 32 elements for at least two sets.

Step-by-step explanation:

Since we have given that

n(A) = 23

n(B) = 23

n(C) = 23

n(A∪B∪C) = 37

As we know the rule of sets:

n(A∪B∪C)=n(A)+n(B)+n(C)-n(A∩B)-n(B∩C)-n(C∩A)+n(A∩B∩C)

37=23+23+23-n(A∩B)-n(B∩C)-n(C∩A)+n(A∩B∩C)

37-69=-(n(A∩B)+n(B∩C)+n(C∩A)-n(A∩B∩C))

32=n(A∩B)+n(B∩C)+n(C∩A)-n(A∩B∩C)

Hence, there are 32 elements for atleast two sets.