Question

2 Eight times of a number riduced by
10 is equal to the sum of six times
the number and 4. Find the number​

Answer 1

Step-by-step explanation:

Let the number be x

According to question,

8x - 10 = 6x + 4

8x - 6x = 4 + 10

2x = 14

$x = \frac{14}{2}$

x = 7

The number = 7

Answer 2

Answer:

The required number is 7

Step-by-step explanation:

Given :

Eight times of a number reduced by 10 is equal to the sum of six times the number and 4

To find :

the number

Solution :

Let the number be 'a'

Eight times the number = 8 × a = 8a

Eight times the number reduced by 10 = 8a – 10

Six times the number = 6 × a = 6a

sum of six times the number and 4 = 6a + 4

As given,

8a – 10 = 6a + 4

8a – 6a – 10 = 4

2a – 10 = 4

2a = 4 + 10

2a = 14

a = 14/2

a = 7

Therefore, the number is 7

Verification :

Put a = 7,

Eight times the number = 8 × 7 = 56

Eight times the number reduced by 10 = 56 – 10 = 46

Six times the number = 6 × 7 = 42

sum of six times the number and 4 = 42 + 4 = 46

Eight times the number reduced by 10 is equal to the sum of six times the number and 4

Hence verified!