Question

2 electric bulbs have 60W and 100W rating at 220 V ratio of their resistances is

Answer 1

using P=VI formula
I ( current of 1st electric bulb ) = P/V
So, I=60/220=3/11A ..... (1)
then now , let
í ( current of 2nd bulb )=P/V
so, í=100/220=5/11 A ..... (2)
now using (1) and (2) and V=IR formula ( ohm's law )
R ( resistance of 1st bulb ) /
R' ( resistance of second bulb ) = V/I / V/Í= Í/I
= 5/11/3/11
= 5/3
Hence required ratio is 5:3

Answer 2

Answer:

it wil be 5:3 it is the correct answer dear mark me as brainlist