Question

2 equally charge particale hold3.20 a part one released from rest.acceration of first particle is observed to be 7.22m/s£ that of 2nd particale to be 9.16m/s . mass of first particale is 6.31 *10kg find mass of 2nd particale magnitude of common charge​

Answer 1

Step-by-step explanation:

With a understood to mean the magnitude of acceleration. Newton's second and third law lead to

m

2

a

2

=m

1

a

1

⇒m

2

=

9.0 m/s

2

(6.3×10

−7

kg)(7.0 m/s

2

)

=4.9×10

−7

kg

Answer 2

There is potty in your head