Question

2 ese kramagat visham dhanamak purnank gyat kijiye jinke vargo ka yog 290 ho​

Answer 1

11  & 13 ese kramagat visham dhanamak purnank  jinke vargo ka yog 290

Step-by-step explanation:

2 ese kramagat visham dhanamak purnank  jinke vargo ka yog 290 ho​

2n - 1   & 2n+ 1

(2n - 1)²  + (2n + 1)² = 290

=> 4n² + 1 - 4n + 4n² + 1 + 4n = 290

=> 8n²  = 288

=> n² = 36

=> n = 6

2n-1 = 11

2n+1 = 13

11  & 13 ese kramagat visham dhanamak purnank  jinke vargo ka yog 290

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