Question

2, Estimate the number of electrons in 10 g of water and
find charge on them. (Ans. 3.334 x 102, 5.335 x 105C]
​

Answer 1

Explanation:

1.

moles of water = 10/18= 0.55

in 1 mol of water= 6*10^23 molecules

0.55 mol of water= 0.55*6*10^23 molecules

in 0.55 mol of water no of electrons

H2O= 2e+ 8e= 10e

so total electrons in water of 0.55 mol is

0.55*6*10^23*10

33*10^23= 3.3*10^24 electrons

I have taken Avogadro's number as 6*10^23 so number after decimal may vary

2. since charge on an electron is 1.6021*10^-19

so charge on 0.55 mol of water

1.6021*10^-19*3.3*10^24

=5.3*10^5C

hope it helps

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