Question

2.
Evaluate the following
(i) (101)2
by using identity​

Answer 1

Answer:

(101)=(100+1) (a+b)^2=a^2+b^2+2ab)

= 10000+1+200

= 10201

Answer 2

Answer:

$(101) { }^{2} \\ (100 + 1) {}^{2} \\ \\ (a + b) {}^{2} = a {}^{2} + b {}^{2} + 2ab \\ \\ here \: a = 100 \\ b = 1 \\ \\ = (100) {}^{2} + (1) {}^{2} + 2 \times 100 \times 1 \\ = 10000 + 1 + 200 \\ = 10201 \\ \\ please \: mark \: me \: as \: brainlist \:$