Question

2 Expand ( 2 − 4 + 3 )^2 using special identity

Answer 1

Answer:

4a²+16b²+9c²-16ab-24bc+12ca

Step-by-step explanation:

We have used the identity,

(a+b+c)² = a²+b²+c²+2ab+2bc +2ca.

(2a-4b+3c)²

= (2a)²+(-4b)²+(3c)²+(2×2a×-4b)+(2×-4b×3c)+(2×3c×2a)

= 4a²+16b²+9c²-16ab-24bc+12ca

U have missed the variables dude. But if there are no variables then consider the answer below.

Answer:

1

Step-by-step explanation:

We have used the identity,

(a+b+c)² = a²+b²+c²+2ab+2bc +2ca.

(2-4+3)²

= (2)²+(-4)²+(3)²+(2×2×-4)+(2×-4×3)+(2×3×2)

= 4+16+9-16-24+12

= 1

OR

(2-4+3)² = 1² = 1

Answer 2

Answer:

Answer is 1

Step-by-step explanation:

(2-4+3)^2

=(-2+3)^2

=(1 )^2

=1

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