Math, asked by mamatamanyata, 5 hours ago

2. Expand:(sinA - 2cosA)2​

Answers

Answered by sandy1816
1

\large ( {sinA - 2cosA})^{2}  \\ \large =  {sin}^{2} A + 4 {cos}^{2} A - 2sinA2cosA \\ \large =  {sin}^{2} A +  {cos}^{2} A + 3 {cos}^{2} A - 2.2sinA \: cosA \\ \large  = 1 + 3 {cos}^{2} A - 2sin2A

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