Math, asked by mansijoshi2453, 1 day ago

2. Expansion of log (1+ x)1/xin ascending powers of x is ...

Answers

Answered by yiennareignmontefalc

0

Answer:

i=

x+1

nx

Step-by-step explanation:

Step 1: Flip the equation.

inx=x+1

Step 2: Divide both sides by nx.

inx

nx. = x+1

nx

i=x+1

nx

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