Question

2: Express the ratios cos A, tan A and sec A in terms of sin A.
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Answer 1

Answer

Cos A = Sin(90-A)

Answer 2

Answer:

$\cos A =\pm\sqrt{1-\sin^2 A}\\\\\tan A=\frac{\sin A}{\pm\sqrt{1-\sin^2 A}}\\\\\sec A= \frac{1}{{\pm\sqrt{1-\sin^2 A}}}$

Step-by-step explanation: