Question

2 F electricity was passed through molten FeO. Weight of iron metal ( tomic Wt=56) deposited at cathode (in g) is​

Answer 1

Answer:

Fe

2+

+2e

−

→Fe

n=2 as 2 electrons are exchanged in this reaction

3F charge is passed which implies 3 moles electrons are passed.

1 mole of Fe is formed when 2 moles of electrons are passed.

For 3 moles of electrons passed 1.5 moles of Fe will be formed.

mass of iron deposited=56×1.5=84g

hope that helps ✌

Answer 2

Answer:

56g of iron metals gets deposited at cathod.

Explanation:

Given :

Electricity passed = 2F

Solution = Molten FeO

Atomic weight of Fe = 56

To find : Iron deposited at cathod

Solution :

We know that,

2 faradays of electricity = 2 moles of electron.

For Ferrous,

$Fe^{+2}$ + 2e = Fe

∴Therefore 2 moles of electron requires 1 mole of Fe.

Now,

1 mole of Fe = 1 * 56

∵ 1 mole of Fe = 56 g

Therefore,

56g of iron metals gets deposited at cathod.

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