Question

2. Factorise the following:
a) b²m + b²n = 62(mm
b) 54x+y + 24xy
c) 10xy - 5y + 8 - 16x
d) 48x’y + 36x2y2 + 24x3y3
e) x²yz + 4xy – 24x3
please solve this in full steps explained please​

Answer 1

★ Solution :—

• We are supposed to Factorise the given terms.
• All we have to do is take some terms common.
• The terms, which are common in the whole polynomial are supposed to be taken outside the bracket.

${\underline{\textit{\textbf{First~Part:}}}}$

$\mapsto \rm \: {b}^{2} m + {b}^{2} n \\ \\ \mapsto \rm \: {b}^{2} (m + n)$

${\underline{\textit{\textbf{Second\;Part:}}}}$

$\mapsto \rm \: 54 {x}^{2} y + 24xy \\ \\ \mapsto \rm \: 6xy(9x + 4)$

${\underline{\textit{\textbf{Third\;Part:}}}}$

$\mapsto \rm \: 10xy - 5y + 8 - 16x \\ \\ \mapsto \rm \: 5y(2x - 1) - 8(2x - 1) \\ \\ \mapsto \rm \: (5y - 8)(2x - 1)$

${\underline{\textit{\textbf{Fourth\;Part:}}}}$

$\mapsto \rm \: 48 {x}^{3} y + 36 {x}^{2} {y}^{2} + 24 {x}^{3} {y}^{3} \\ \\ \mapsto \rm \: 12 {x}^{2} y(4x + 3y + 2x {y}^{2} )$

${\underline{\textit{\textbf{Fifth\;Part}}}}$

$\mapsto \rm \: {x}^{2} yz + 4 {x}^{3} y - 24 {x}^{3 } \\ \\ \mapsto \rm \: {x}^{2} (yz + 4xy - 24x)$

Answer 2

Answer:

★ Solution :—

\begin{gathered} \\ \end{gathered}

We are supposed to Factorise the given terms.

All we have to do is take some terms common.

The terms, which are common in the whole polynomial are supposed to be taken outside the bracket.

{\underline{\textit{\textbf{First~Part:}}}}

First Part:

\begin{gathered} \mapsto \rm \: {b}^{2} m + {b}^{2} n \\ \\ \mapsto \rm \: {b}^{2} (m + n)\end{gathered}

↦b

2

m+b

2

n

↦b

2

(m+n)

SecondPart:

Step-by-step explanation:

:

54x

2

y+24xy

↦6xy(9x+4)

third part

↦10xy−5y+8−16x

↦5y(2x−1)−8(2x−1)

↦(5y−8)(2x−1)

FourthPart:

48x

3

y+36x

2

y

2

+24x

3

y

3

↦12x

2

y(4x+3y+2xy

2

)

fifth part

4x

3

y−24x

3

↦x

2

yz↦x

2

(yz+4xy−24x)