Question

2) Factorise (x2 - 6x)2 - 8(x2 - 6x + 8) - 64​

Answer 1

Answer:

(x

2

−6x)

2

−8(x

2

−6x+8)−64

=(x

2

−6x)

2

−8(x

2

−6x)−64−64

=(x

2

−6x)

2

−8(x

2

−6x)−128

Let x

2

−6x=z

z

2

−8z−128

z

2

−16z+8z−128

z(z−16)+8(z−16)

(z−16)(z+8)

substitute the value of z

(x

2

−6x−16)(x

2

−6x+8)

(x

2

−8x+2x−16)(x

2

−4x−2x+8)

[x(x−8)+2(x−8)][x(x−4)−2(x−4)]

(x−8)(x+2)(x−4)(x−2)

Answer 2

Answer:

$(4x)6(4x + 8) - 64 \\ (4x)6(12x) - 64 \\ (4x)(72x) - 64$

Step-by-step explanation:

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(4x) (72x)-64