Question

2.Factorize the following: v) 12x^2 + 17x + 6

Answer 1

Step-by-step explanation:

hope this will help you

Answer 2

Answer:

$\bigstar{\bold{Zeros\:are\:-\dfrac{2}{3}\:and\:-\dfrac{3}{4} }}$

Step-by-step explanation:

$\Large{\underline{\underline{\bf{Given:}}}}$

• p(x) = 12x² + 17x + 6

$\Large{\underline{\underline{\bf{To\:Find:}}}}$

• Zeros of the polynomial

$\Large{\underline{\underline{\bf{Solution:}}}}$

→ By using factor theorem,

 $x=\dfrac{-b\pm\sqrt{b^{2}-4ac } }{2a}$

where a = 12, b = 17, c = 6

Substituting the given datas we get,

$x=\dfrac{-17\pm\sqrt{17^{2} -4\times 12\times 6} }{2\times 12}$

$x=\dfrac{-17\pm\sqrt{289-288} }{24}$

$x=\dfrac{-17\pm 1}{24}$

Either

$x=\dfrac{-17+1}{24}$

$x=\dfrac{-16}{24}$

$x=-\dfrac{2}{3}$

or

$x=\dfrac{-17-1}{24}$

$x=\dfrac{-18}{24}$

$x=-\dfrac{3}{4}$

$\boxed{\bold{Zeros\:are\:-\dfrac{2}{3}\:and\:-\dfrac{3}{4} }}$

$\Large{\underline{\underline{\bf{Notes:}}}}$

→ The zeros of a polynomial can be found out by

• Factorisation method
• Splitting the middle term
• Completing the square method