Question

2 farmers A and B had 30 cows between them.
They sold them at different prices but each
received the same amount. If A had sold his cows
at the price at which B had sold, he would have
received Rs. 320 and if B had sold his cows at the
price at which A had sold, he would have received
Rs. 245. Find the number of cows each had.
Ans
A - 16 COWS
B - 14 COWS​

Answer 1

Answer:

Answer:

Step-by-step explanation:

Let the number of sheep of A be X.

Let the number of sheep of B be Y.

Therefore,

X+Y =30 (1)

Let the selling price of A's sheep be P.

Let the selling price of B's sheep be Q.

Now as per question,

P×X =Q× Y (2)

Also,

X×Q= 3200.

Or, Q=(3200/X)

Again,

Y×P =2450.

P=(2450/Y)

Now putting the value of P and Q in equation (2) we get.

(2450/Y)X = (3200/X) Y

Step-by-step explanation: