2 farmers A and B had 30 cows between them.
They sold them at different prices but each
received the same amount. If A had sold his cows
at the price at which B had sold, he would have
received Rs. 320 and if B had sold his cows at the
price at which A had sold, he would have received
Rs. 245. Find the number of cows each had.
Ans
A - 16 COWS
B - 14 COWS
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Answer:
Answer:
Step-by-step explanation:
Let the number of sheep of A be X.
Let the number of sheep of B be Y.
Therefore,
X+Y =30 (1)
Let the selling price of A's sheep be P.
Let the selling price of B's sheep be Q.
Now as per question,
P×X =Q× Y (2)
Also,
X×Q= 3200.
Or, Q=(3200/X)
Again,
Y×P =2450.
P=(2450/Y)
Now putting the value of P and Q in equation (2) we get.
(2450/Y)X = (3200/X) Y
Step-by-step explanation:
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