Question

2) Find 104 term of AP-43.-37.-31.​

Answer 1

first term = -43

common difference = -6

$tn = a + (n - 1)d \\ \\ 104 = - 43 + (n - 1) - 6 \\ \\ 104 = - 43 - 6n + 6 \\ \\ 104 = - 37 - 6n \\ \\ 141 = - 6n \\ \\ n = \frac{ - 141}{6 } \\ \\ n = - 23.5$

Answer 2

${\huge{\bold{\purple{\bigstar{\boxed{\bf{Question}}}}}}}$

• Find the 104th term of AP -43, -37 , - 31 ...

${\huge{\bold{\purple{\bigstar{\boxed{\bf{Answer}}}}}}}$

${\bold{\blue{\boxed{\bf{Given}}}}}$

• first term = a = -43
• common diff. = d = +6
• no. of times =n= 104

${\bold{\blue{\boxed{\bf{To\:find}}}}}$

• $\bold{a_{104}}= ???$

${\bold{\blue{\boxed{\bf{ Formulae\:used }}}}}$

• $\bold a_n = a + (n-1)d$

${\bold{\blue{\boxed{\bf{ Solution}}}}}$

$a_{104} = -43 + (104-1)\times + 6$

$a_{104} = -43 + 103 \times +6$

$a_{104} = -43 + 618$

$a_{104} = +575$

${\bold{\blue{\boxed{\boxed{\bf{a_{104} = +575}}}}}}$

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$\sf{\bold{\green{\underline{\underline{Extra\: Information}}}}}$

• A progression is a sequence of numbers whose each term is related to its predecessor and successor by a uniform law .

• An airthmetic progression is a sequence (series) of numbers in which each terms can be obtained by adding a certain quantity to its Preceding term

• In an AP , the difference between two consecutive terms is called common difference and is denoted by letter " d "

• The first term of AP is denoted by " a "