2. Find a quadratic polynomial each with the given numbers as the sum and product of its
zeroes respectively =√2,1/3.
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Answer:
3x^2 - 3√2x +1
Step-by-step explanation:
let the zeroes be x and y
x.y = 1/3
x+y = root 2
so the polynomial is
x^2 - (sum of zeroes)x +product of zeroes
= x^2 - √2 +1/3
= 3x^2 - 3√2x +1
hope it helps mark it the branliest
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