Math, asked by samarth9034, 7 months ago

2. Find an angle which is four times of its supplement.​

Answers

Answered by Anonymous
0

Step-by-step explanation:

It's pretty easy

It's pretty easyIfsum of two angles say a and b =180° then they are called supplementary angles

It's pretty easyIfsum of two angles say a and b =180° then they are called supplementary anglesAccording to question

It's pretty easyIfsum of two angles say a and b =180° then they are called supplementary anglesAccording to questionSupplement of a is 180°-b

It's pretty easyIfsum of two angles say a and b =180° then they are called supplementary anglesAccording to questionSupplement of a is 180°-bSo,

It's pretty easyIfsum of two angles say a and b =180° then they are called supplementary anglesAccording to questionSupplement of a is 180°-bSo,b=4(180-b)

It's pretty easyIfsum of two angles say a and b =180° then they are called supplementary anglesAccording to questionSupplement of a is 180°-bSo,b=4(180-b)b=720–4b

It's pretty easyIfsum of two angles say a and b =180° then they are called supplementary anglesAccording to questionSupplement of a is 180°-bSo,b=4(180-b)b=720–4b5b=720

It's pretty easyIfsum of two angles say a and b =180° then they are called supplementary anglesAccording to questionSupplement of a is 180°-bSo,b=4(180-b)b=720–4b5b=720b=144

It's pretty easyIfsum of two angles say a and b =180° then they are called supplementary anglesAccording to questionSupplement of a is 180°-bSo,b=4(180-b)b=720–4b5b=720b=144Therefore 144 is 4 times it's supplement

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