Question

2. Find BC, if the area of the triangle ABC is 36 cm and height AD is 6 cm​

Answer 1

Answer:

12cm

Step-by-step explanation:

area of triangle=1/2bh

on substituting the values

36=1/2*b*6

36/6=1/2*b

6=½*b

6*2=b

12=b

Answer 2

Given : Area of Triangle ABC is 36 cm² and Height or AD of Triangle is 6 cm .

Need To Find : B C or Base of Triangle.

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❍Let's Consider the Base of Triangle be x cm.

As, We know that ,

$\star\boxed {\pink{\sf{ Area_{(Triangle)} = \dfrac{1}{2} \times b \times h \:sq.units}}}$

Where ,

• b is the Base of Triangle and h is the Height of Triangle.

⠀⠀⠀⠀⠀⠀$\underline {\frak{\star\:Now \: By \: Substituting \: the \: Given \: Values \::}}$

$\qquad:\implies \sf{ 36 = \dfrac{1}{\cancel {2}} \times \cancel {6} \times x }$

$\qquad:\implies \sf{ 36 = 3 \times x }$

$\qquad:\implies \sf{ \cancel {\dfrac{36}{3}} = x }$

⠀⠀⠀⠀⠀$\underline {\boxed{\pink{ \mathrm {  x = 12\: cm}}}}\:\bf{\bigstar}$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm { Hence, \:Base\:BC \:of\:Triangle \:is\:\bf{12\: cm}}}}$

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$\large {\boxed{\sf{\mid{\overline {\underline {\star More\:To\:know\::}}}\mid}}}$

• $\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}$

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