2) Find 'n', if S, is sum of all odd numbers from 1 to 150.
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Answer:
5625
Step-by-step explanation:
Clearly, the odd natural numbers from 1 to 150 are 1,3,5,...,149.
This is an AP with first term a=1, common difference d=2 and last term a
n
=l=149.
Let there be n terms in this AP.
Then,
a
n
=149
⇒a
n
=a+(n−1)d
149=1+(n−1)×2
149=1+2n−2
2n=150
∴n=75
∴ required sum =S
n
=
2
n
[a+l]=
2
75
[1+149]=5625
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