Question

2. Find number of oxygen atoms present in 100 mg
of Caco
(Atomic mass of Ca = 40 u, C = 12 u, O = 16 u)
(1) 6.02 x 1023
(2) 6.02 x 1020
(3) 1.806 x 1021 (4) 1.204 x 1020

Answer 1

Answer:

100 g of Calcium Carbonate (100,000 mg of Calcium Carbonate) has 3 moles of Oxygen atoms = 3 x 6.022 x 10^23 Oxygen atoms.