Math, asked by priyavarghese8383, 11 months ago

2. / Find out the mean deviation from mean and
median from the following series.
Age (in years) 0-10 10-20 20-30 30-40
No. of persons 20 25 32 40
Age (in years) 40-50 50-60 60-70 70-80
No. of persons 42 35 10 08
Also compute co-efficient of mean deviation​

Answers

Answered by amitnrw
3

Given  : Age (in years) 0-10 10-20 20-30 30-40

No. of persons 20 25 32 40

Age (in years) 40-50 50-60 60-70 70-80

No. of persons 42 35 10 08

To Find :  mean deviation from mean

Solution:

Age       Mean X  personsf   fX  

0-10           5            20         100

10-20        15            25          375

20-30        25          32         800  

30-40        35          40          1400  

40-50        45          42          1890  

50-60        55          35           1925  

60-70         65          10           650        

70-80        75           08           600

                             212              7740

∑ f = 212

∑fX = 7740

Mean = ∑fX/∑ f

Mean = 7740/212  = 36.5

f     |X-Mean|  f. |X-Mean|

20 31.5        630

25 21.5        537.5

32 11.5        368

40 1.5         60

42 8.5        357

35 18.5        647.5

10 28.5 285

8 38.5 308

                        3193

Mean deviation from Mean = ∑f |X-Mean| / ∑ f

mean deviation from mean   =  3193/212 = 15.06

co-efficient of mean deviation​  = 15.06/36.5 = 0.41

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