Question

2 Find p(0) if p(y)=y2−y+1 please fast urgent

Answer 1

Answer:

p(0)

p(0)=0^2-0+1

p(0)=0+1

p(0)=1

Step-by-step explanation:

hope it is helpful mark as brainleist

Answer 2

To find:-

p(0) = ?

Given,

p(y) = y²-y+1

Solution:-

p(0) = 0²-0+1

=> p(0) = 1 .

Hope it's helpful to you.

Please mark as Brainliest answer.

(•‿•)(・∀・)◉‿◉｡◕‿◕｡