Question

2. Find p(0), p(1) and p(2) for each of the following polynomials.
1) p(y)=2 + y + 2y^2 - y^3​

Answer 1

Step-by-step explanation:

p(0) = 2+0+2(0)^2-2^3

= 2-8

= -6

p(1) = 2+1+2-1

= 4

p(2) = 2+2+8-8

= 4